Answer
$$y+9 = 16(x+2)$$
Work Step by Step
To find the linearization we first need to calculate the slope by taking the derivative.
$$f'(x) = 3x^2-2x$$
$$f'(-2) = 3(-2)^2-2(-2)$$
$$f'(-2) = 16$$
We also need to find the y-value at the given $a$ value,
$$f(-2) = -8 -4+3= -9$$
Using point-slope form,
$$y+9 = 16(x+2)$$
