Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.8 Related Rates - 2.8 Exercises - Page 185: 12

Answer

$6\text{ cm}~~\text{per}~~\text{s}$.

Work Step by Step

Using the chain rule it follows: $$\frac{dy}{dt}=\frac{dy}{dx} \cdot \frac{dx}{dt}$$ Since the $y$ coordinate is decreasing it follows that the rate $\frac{dy}{dt} \lt 0$ therefore: $$ \frac{dy}{dt}=-3$$ $$-3=\frac{dy}{dx} \cdot \frac{dx}{dt}$$ Using the implicit differentiation to $xy=8$ it follows: $$(x)'y+x(y)'=(8)'$$ $$y+x\frac{dy}{dx}=0$$ $$\frac{dy}{dx}=-\frac{y}{x}$$ $$\frac{dy}{dx}|_{x=4,y=2}=-\frac{2}{4}=-\frac{1}{2}$$ So: $$-3=-\frac{1}{2} \cdot \frac{dx}{dt}$$ $$-3\cdot 2 =-\frac{dx}{dt}$$ $$6=\frac{dx}{dt}$$ The answer is $6\text{ cm}~~\text{per}~~\text{s}$.
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