Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.7 Rates of Change in the Natural and Social Sciences - 2.7 Exercises - Page 180: 33

Answer

$\approx$ $-0.24$ $K/min$

Work Step by Step

$PV$ = $nRT$ $T$ = $\frac{PV}{nR}$ = $\frac{PV}{10(0.0821)}$ = $\frac{1}{0.821}PV$ $\frac{dT}{dt}$ = $\frac{1}{0.821}[P(t)V'(t)+P'(t)V(t)]$ = $\frac{1}{0.821}[(8)(-0.15)+(10)(0.10)]$ $\approx$ $-0.24$ $K/min$
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