Answer
(a)
$A(x)$ = $\frac{p(x)}{x}$
$A'(x)$ = $\frac{xp'(x)-p(x)}{x^{2}}$
$A'(x)$ $\gt$ $0$ then $A(x)$ is increasing; that is, the average productivity increases as the size of the workforce increases.
(b)
$p'(x)$ is greater than the average productivity then
$p'(x)$ $\gt$ $A(x)$
$p'(x)$ $\gt$ $\frac{p(x)}{x}$
$xp'(x)$ $\gt$ $p(x)$
$xp'(x)-p(x)$ $\gt$ $0$
$\frac{xp'(x)-p(x)}{x^{2}}$ $\gt$ $0$
$A'(x)$ $\gt$ $0$
Work Step by Step
(a)
$A(x)$ = $\frac{p(x)}{x}$
$A'(x)$ = $\frac{xp'(x)-p(x)}{x^{2}}$
$A'(x)$ $\gt$ $0$ then $A(x)$ is increasing; that is, the average productivity increases as the size of the workforce increases.
(b)
$p'(x)$ is greater than the average productivity then
$p'(x)$ $\gt$ $A(x)$
$p'(x)$ $\gt$ $\frac{p(x)}{x}$
$xp'(x)$ $\gt$ $p(x)$
$xp'(x)-p(x)$ $\gt$ $0$
$\frac{xp'(x)-p(x)}{x^{2}}$ $\gt$ $0$
$A'(x)$ $\gt$ $0$