Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.4 Derivatives of Trigonometric Functions - 2.4 Exercises - Page 151: 39

Answer

$\frac{5}{3}$

Work Step by Step

Since $\lim\limits_{x \to 0}$ $\frac{sin x}{x}$ = 1 and $\lim\limits_{x \to 0}$ $\frac{sin 5x}{3x}$ has the same exponential power on both top and bottom, $\lim\limits_{x \to 0}$ $\frac{sin 5x}{3x}$ = $\frac{5}{3}$
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