Answer
$(2t - c)sin(t) + t^2cos(t)$
Work Step by Step
$y= ccos(t)+ t^2sin(t)$
$y'= -csin(t) + (2tsin(t) + t^2cos(t))$
$y' = 2tsin(t) - csin(t) + t^2cos(t)$
$y'= (2t -c)sin(t) + t^2cos(t)$
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