Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.4 Derivatives of Trigonometric Functions - 2.4 Exercises: 14

Answer

Differentiate $y=\frac{\sin t}{1 +\tan t}$ $y'=\frac{\cos t + \sin t -\tan t\sec t}{(1+\tan t)^2}$

Work Step by Step

Differentiate using quotient rule and trig rules. $y' =\frac{\cos t(1+\tan t) - \sin t(\sec ^2t)}{(1+\tan t)^2}$ $=\frac{\cos t + \sin t -\tan t\sec t}{(1+\tan t)^2}$
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