Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.1 Derivatives and Rates of Change - 2.1 Exercises - Page 115: 46

Answer

The rate of change of the temperature after 1 hour is approximately $-\frac{5}{6}$ degrees Fahrenheit per minute.

Work Step by Step

The slope of the tangent line at t=60 is the rate of change of the temperature at this time. Let's say that this tangent line is represented by the function T'(t). Using that tangent line given in the problem image, we can estimate that T'(30)=150 and T'(60)=125. We can plug this into the slope formula $(m=\frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1}})$. This gives us $\frac{125-150}{60-30} = \frac{-50}{60} = \frac{-5}{6}$ Therefore, the rate of change of the temperature at $t=60$ is approximately -5/6 degrees Fahrenheit per minute.
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