Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.1 Derivatives and Rates of Change - 2.1 Exercises - Page 115: 43

Answer

32 m/s

Work Step by Step

First you start by taking the derivative of the equation. $f(t)= 80t-6t^{2} $ becomes $f ' (t)= 80- 12t$ Now that we know that t=4, we can substitute the number in. $80 - 12(4)= f(t)$ $80 - 48= 32 m/s$
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