Answer
$j'(x)=2.4x^\frac{7}{5}$
Work Step by Step
$j(x)=x^\frac{12}{5}+e^\frac{12}{5}$
$j'(x)=2.4x^\frac{7}{5}+0=2.4x^\frac{7}{5}$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 2 - Derivatives - 2.1 Derivatives and Rates of Change - 2.1 Exercises - Page 114: 25
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