Answer
$y=c_{1}e^{3x}+c_{2}e^{-4x}$
Work Step by Step
$r^{2}+r-12=0$
$(r-3)(r+4)=0$
So general formula and general solution add up to make the auxiliary equation which is
$ar^2+by+c=0$
therefore the final answer would be
$y=c_{1}e^{3x}+c_{2}e^{-4x}$
