Answer
True
Work Step by Step
Since, D_{k}f(x,y,z)=∆ f.k$
$=[f_{x}(x,y,z),f_{y}(x,y,z),f_{z}(x,y,z)].(0,0,1)$
$=f_{z}(x,y,z)$
Hence, the statement is true.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 14 - Partial Derivatives - Review - True-False Quiz - Page 1022: 4
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