Answer
$ -8.83 k Pa$
Work Step by Step
Write the differential form such as:
$dP=\dfrac{\partial P}{\partial V} dV + \dfrac{\partial P}{\partial T} dT$
$dP=\dfrac{-8.31 T}{V^2} \times dV + \dfrac{8.31}{V} dT$
and
$\triangle P \approx \dfrac{-8.31 T}{V^2} \times \triangle V + \dfrac{8.31 T}{V} \times \triangle T$
Need to plug the given values.
$\triangle P \approx \dfrac{-8.31 \times 310}{(12)^2} ((0.3)) + (\dfrac{8.31}{12}) \times (-5) \approx -8.83 k Pa$
