Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 14 - Partial Derivatives - 14.3 Partial Derivatives - 14.3 Exercises: 15

Answer

$$f_x = 2xy - 0 = 2xy$$ $$f_y = x^2 - 12xy$$

Work Step by Step

To find $f_x$, we treat $y$ as a constant and differentiate with respect to $x$. Thus $$f_x = 2xy - 0 = 2xy.$$ Similarly, to find $f_y$, we treat $x$ s a constant and differentiate with respect to $y$. Thus $$f_y = x^2 - 12xy.$$
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