## Calculus 8th Edition

The domain is given by $$\mathcal{D}=\{(x,y)|y\geq x^2,x\neq\pm1\},$$ and it is presented on the graph below (red lines are excluded from it)
Here, we have two constraints: 1.The argument of the square root has to be nonnegative i.e. $$y-x^2\geq0\Rightarrow y\geq x^2.$$ 2. The denominator must not be zero i.e. $$1-x^2\neq0\Rightarrow x\neq\pm1.$$ This means that the domain is the region including and above the parabola $y=x^2$ with the vertical lines $x=\pm1$ excluded from is. So we write for the domain $$\mathcal{D}=\{(x,y)|y\geq x^2,x\neq\pm1\},$$ and it is presented in the figure below (red lines are excluded from it)