Answer
Paraboloid
Work Step by Step
$x=y^2+z^2-2y-4z+15$
$x=(y^2-2y)+(z^2-4z)+15$
$x=(y-1)^2+(z-2)^2$
The equation is in the form of a Paraboloid that has vertex $(0,1,2)$ and opens in positive x-axis.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 12 - Vectors and the Geometry of Space - Review - Exercises - Page 883: 36
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