# Chapter 12 - Vectors and the Geometry of Space - Review - Exercises: 16

$x=1+3t,y=2t,z=−1+t$

#### Work Step by Step

Given: $x=4+3t,y=2t,z=−2+t$ The direction of the vectors is $<3,2,1>$ Formula for a line: $r=r_0+tv$ where$r_0$ is the starting point vector and $v$ is the direction vector. $r=<1,0,−1>+t<3,2,1>$ Therefore, the parametric equations of the line are: $x=1+3t,y=2t,z=−1+t$

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.