Answer
$\approx 17 Nm$
Work Step by Step
$| \tau| =|r \times F|$
Here, $|F|=50 N$ and $|r|=40 cm =0.4 m$
In this question $ \theta =60 ^\circ$ because $F$ makes an angle with $r$ a acute angle.
$| \tau| =|r \times F|$
$| \tau| =(0.4) (50) sin 60^\circ$
$| \tau|\approx 17.32 Nm$ or, $\approx 17 Nm$