Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 12 - Vectors and the Geometry of Space - 12.1 Three-Dimensional Coordinate Systems - 12.1 Exercises - Page 837: 18

Answer

Center is at (-4, 3, -1) and the radius is 3

Work Step by Step

$x^{2} + y^{2} + z^{2} + 8x - 6y + 2z = -17 $ $x^{2} + 8x + y^{2} - 6y + z^{2} + 2z = -17 $ $x^{2} + 8x +16 + y^{2} - 6y + 9 + z^{2} + 2z + 1 = -17 + 16 + 9 + 1 $ $(x + 4)^{2} + (y-3)^{2} + (z+1)^{2} = 9 $ This is indeed a sphere, the center is at (-4, 3, -1) and the radius is 3
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