Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - Review - True-False Quiz - Page 825: 19

Answer

TRUE

Work Step by Step

$0.99999...=0.9+0.09+0.099+..=\Sigma _0^\infty\frac{9}{10}\times (\frac{1}{10})^{n}$ $=\frac{9/10}{1-\frac{1}{10}}$ $=1$ Hence, the statement is true.
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