Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.3 The Integral Test and Estimates of Sums - 11.3 Exercises - Page 766: 31

Answer

convergent for $p\lt -1$.

Work Step by Step

$\int_{1}^{\infty}x(1+x^{2})dx=\int_{2}^{\infty}\frac{1}{2}u^{p}du=\frac{1}{2}(\infty^{p}-2^{p})$ which is convergent for $p\lt -1$.
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