Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.3 The Integral Test and Estimates of Sums - 11.3 Exercises - Page 766: 30

Answer

convergent for $p\gt 1$.

Work Step by Step

$\int_{3}^{\infty}\frac{1}{xlnx[ln(lnx)]^{p}}dx=\int_{ln(ln3)}^{\infty}\frac{1}{u^{p}}du=\int_{ln(ln3)}^{\infty}u^{-p}du$ which is convergent for $p\gt 1$.
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