Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.1 Sequences - 11.1 Exercises - Page 744: 40

Answer

converges to $0$.

Work Step by Step

$\lim\limits_{n \to \infty}a_{n}=\lim\limits_{n \to \infty}\frac{tan^{-1}n}{n}$ $=\frac{\lim\limits_{n \to \infty}tan^{-1}n}{\lim\limits_{n \to \infty}n}$ $=\frac{\pi/2}{\infty}$ $=0$ The given sequence converges to $0$.
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