Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.1 Sequences - 11.1 Exercises - Page 744: 29

Answer

converges to $1$

Work Step by Step

By continuity of limits, we can take the limit into the exponent of $e$. The limit of $\frac{-1}{\sqrt{n}}$ is 0 as $n \to \infty$. Hence the sequence converges to $e^0 = 1$.
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