Answer
$18$
Work Step by Step
Given: $r^2=9 cos 5 \theta$
$Area,A=\int_{- \pi/10}^{\pi/10}\frac{r^2}{2}d\theta$
$=\int_{- \pi/10}^{\pi/10}\dfrac{9cos5 \theta}{2}d\theta$
$=10[\dfrac{9sin5 \theta}{10}]_{- \pi/10}^{\pi/10}$
$=18$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 10 - Parametric Equations and Polar Coordinates - Review - Exercises - Page 730: 31
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