Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Review - Exercises: 32

Answer

$-1$

Work Step by Step

$a > b\Rightarrow \left| b-a\right| =-\left( b-a\right) \Rightarrow \lim _{v\rightarrow 4^+}\dfrac {4-v}{\left| 4-v\right| }=\dfrac {4-v}{-\left( 4-v\right) }=-1$
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