Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - Principles of Problem Solving - Problems - Page 103: 12

Answer

See below

Work Step by Step

We can prove this by induction. $S(1) = 1$ Assuming $S(n) = n^2$ then, $S(n+1) = S(n) +a_{n+1}=S(n) + (2n+1) = n^2 + 2n +1 = (n+1)^2$ Which shows the formula holds.
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