Answer
See proof below...
Work Step by Step
The remainder when $7^n$ is divided by 6 is always 1 because, $7 = 1 $mod$ 6$ and $1^n =1$ for all positive n.
Thus $1^n - 1 = 1-1 = 0$
Since the remainder is always 0, it must be divisible.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - Principles of Problem Solving - Problems - Page 103: 11
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