Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - 1.8 Continuity - 1.8 Exercises - Page 92: 8

Answer

The function is discontinous at $x=-2$ and also shows that $\lim\limits_{x \to 2^-}f(x)=f(2)$ and $\lim\limits_{x \to 2^+}f(x)\ne f(2)$.

Work Step by Step

The graph of $y=f(x)$ must have discontinuity at $x=-2$ with $\lim\limits_{x \to -2^-}f(x)\ne f(-2)$ and also $\lim\limits_{x \to -2^+}f(x)\ne f(-2)$. This graph also shows that $\lim\limits_{x \to 2^-}f(x)=f(2)$ and $\lim\limits_{x \to 2^+}f(x)\ne f(2)$. Which is shown below,
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