Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - 1.6 Calculating Limits Using the Limit Laws - 1.6 Exercises: 28

Answer

0

Work Step by Step

$\lim\limits_{x \to 2}\frac{x^2-4x+4}{x^4-3x^2-4}=\lim\limits_{x \to 2}\frac{(x-2)(x-2)}{(x^2-4)(x^2+1)}=\lim\limits_{x \to 2}\frac{(x-2)(x-2)}{(x+2)(x-2)(x^2+1)}=\lim\limits_{x \to 2}\frac{x-2}{(x+2)(x^2+1)}=\frac{(2)-2}{((2)+2)((2)^2+1)}=\frac{0}{20}=0$
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