Answer
$\lim\limits_{x \to 5}\frac{x^{2}-6x+5}{x-5}=4$
Work Step by Step
$\lim\limits_{x \to 5}\frac{x^{2}-6x+5}{x-5}=\lim\limits_{x \to 5}\frac{(x-5)(x-1)}{x-5}=\lim\limits_{x \to 5}\frac{(x-1)}{1}=\lim\limits_{x \to 5}x-1=5-1=4$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - 1.6 Calculating Limits Using the Limit Laws - 1.6 Exercises - Page 70: 11
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