Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - 1.3 New Functions from Old Functions - 1.3 Exercises - Page 44: 47

Answer

$v(t)=f\circ g(t)$ for $g(t)=t^{2}$ and $f(t)=\sec t\tan t$

Work Step by Step

$f\circ g(t)=f[g(t)]$ Rule of thumb: Ask yourself what would be the last operation if we used a calculator, step by step? (Answer: If R$=t^{2}$ was the current result, we would calculate $\sec t\tan t$) $f(t)=\sec t\tan t$ $v(t)=f(t^{2})$ So, if $g(t)=t^{2}$ and $f(t)=\sec t\tan t$, then $v(t)=f\circ g(t)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.