Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 1 - Functions and Limits - 1.3 New Functions from Old Functions - 1.3 Exercises: 40

Answer

$(f\circ g\circ h) (x)=|2^{\sqrt{x}}-4|$

Work Step by Step

$(f\circ g\circ h) (x)=f[g(h(x))]$ $g(h(x))=2^{h(x)}=2^{\sqrt{x}}$ $f[g(h(x))]=f(2^{\sqrt{x}})=|2^{\sqrt{x}}-4|$
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