Answer
$f$ is not even or odd.
Work Step by Step
$f(x) = 1+3x^3 -x^5$
lets calculate $f(-x)$
$f(-x)=1+3(-x)^3 -(-x)^5=1+3(-1)^3x^3 -(-1)^5x^5$
$=1-3x^3 +x^5\ne f(x) \ne -f(x)$
Therefore $f$ is not even or odd.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - 1.1 Four Ways to Represent a Function - 1.1 Exercises - Page 23: 78
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