Answer
$5x+4y-15=0$ for $-5≤x≤7$
Work Step by Step
$m = \frac{y_2-y_1}{x_2-x_1}=\frac{10-(-10)}{-5-7} = \frac{20}{-12}=\frac{-5}{4}$
$y-y_1=m(x-x_1)$
Using point (-5,10)
$y - 10 = \frac{-5}{4}(x-(-5))$
$4y-40 = -5x -25$
$5x+4y-15=0$
Since this is only over the range of (-5,10) to (7,-10) this applies only to the domain of $-5≤x≤7.$
