Answer
-$\infty$ $\lt$ t $\lt$ +$\infty$
Work Step by Step
Since $\sqrt[3] x$ is valid for any x, positive or negative, there is no restriction for 2t - 1 and f(t) is valid for any real t
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 1 - Functions and Limits - 1.1 Four Ways to Represent a Function - 1.1 Exercises - Page 21: 33
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