Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix G - Complex Numbers - G Exercises: 16

Answer

conjugate: $-1-2\sqrt{2}i$ modulus: 3

Work Step by Step

To find the conjugate of a complex number, we reverse the sign of the imaginary part, like so: $\overline{-1+2\sqrt{2}i}$ $=-1-2\sqrt{2}i$ We find the modulus using the formula $\sqrt{a^2+b^2}$ for $a+bi$: $|-1+2\sqrt{2}i|$ $=\sqrt{(-1)^{2}+(2\sqrt{2})^{2}}$ $=\sqrt{1+8}$ $=\sqrt{9}$ $=3$
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