Answer
$\sum_{i=1}^{6}\frac{1}{i^{2}}$
Work Step by Step
We contract the sum into sigma notation by noting that it follows the pattern of a sum of fractions with 1 on top and squares of integers on the bottom (e.g. $\frac{1}{i^2}$), starting with $\frac{1}{1}$ (e.g. $i=1$), and ending with $\frac{1}{36}$ (e.g. $i=6$).
$\displaystyle \frac{1}{1}+\frac{1}{4}+\frac{1}{9}+\frac{1}{16}+\frac{1}{25}+\frac{1}{36}=\sum_{i=1}^{6}\frac{1}{i^{2}}$