Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix D - Trigonometry - D Exercises: 84

Answer

1355 m

Work Step by Step

Use law of cosines, we have $c^{2}=a^{2}+b^{2}-2ab cos \theta$ As per question: $|AB|^{2}=|AC|^{2}+|BC|^{2}-2|AC||BC| cos 103^{\circ}$ $|AB|^{2}=820^{2}+910^{2}-2(820)(910) cos 103^{\circ}$ $|AB|=\sqrt {820^{2}+910^{2}-2(820)(910) cos 103^{\circ}}$ $|AB|=1355$ m
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