Answer
$ \frac{\pi}{4}$
Work Step by Step
$sinx>cosx$
Let us simplify the above equation.
$sinx=cosx$
Thus, $tanx=1$
Since, $tanx>0$ on first and third quadrant and $tanx<0$ on second and fourth quadrant.
Thus, x must lie on $\frac{\pi}{4},\frac{5 \pi}{4}$
Hence, the solutions for the given equation is $ \frac{\pi}{4}$
