Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix D - Trigonometry - D Exercises: 76

Answer

$ \frac{\pi}{4}$

Work Step by Step

$sinx>cosx$ Let us simplify the above equation. $sinx=cosx$ Thus, $tanx=1$ Since, $tanx>0$ on first and third quadrant and $tanx<0$ on second and fourth quadrant. Thus, x must lie on $\frac{\pi}{4},\frac{5 \pi}{4}$ Hence, the solutions for the given equation is $ \frac{\pi}{4}$
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