Answer
The lines intersect at the point $(1,-2)$
Work Step by Step
The linear equations are not parallel because they do not have the same slope. The slope can be seen by looking at the coefficient of the "$x$-term," and for one equation it is 2 and the other 3.
To find the point of intersection, isolate each equation for $y$:
$2x-y=4\qquad\qquad6x-2xy=10$
$y=2x-4\qquad\qquad2y=6x-10$
$\qquad\qquad\qquad\qquad\quad y=3x-5$
Now set each equation equal to itself to solve for $x$:
$2x-4=3x-5$
$1=x$
Now plug $x=1$ back into either equation to find the corresponding value of $y$:
y=2(1)-4 = 2-4
y=-2
Therefore the point of intersection is $(1,-2)$
