Answer
$x^{2}sinx+2xcosx-2sinx+C$
Work Step by Step
Given $\int x^{2}cosxdx$
Use the Tabular Method.
Derivative | Anti-derivative
(+)$x^{2}|cosx$
(-)$2x|sinx$
(+)$2|-cosx$
(-)$0|-sinx$
$=x^{2}sinx+2xcosx-2sinx+C$
Calculus 10th Edition
by Larson, Ron; Edwards, Bruce H.
Published by
Brooks Cole
ISBN 10:
1-28505-709-0
ISBN 13:
978-1-28505-709-5
Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.2 Exercises - Page 521: 26
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