Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 51

Answer

$\frac 1 2 e^{2x}+10e^x+25x+C$

Work Step by Step

$\frac {dy}{dx}=(e^x+5)^2$ $(e^x+5)^2=e^{2x}+10e^x+25$ $y=\int (e^{2x}+10e^x+25)dx$ $\frac 1 2 e^{2x}+10e^x+25x+C$
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