Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 8

Answer

$\int \frac{du}{a^{2}+u^{2}}$ $u=2t-1$ $a=2$

Work Step by Step

Try it: $u=2t-1$ $du=2dt$ $\int \frac{du}{a^{2}+u^{2}}= \frac{1}{a}arctan\frac{u}{a}+C$ $\frac{1}{2}arctan\frac{2t-1}{2}+C$ $\int \frac{du}{a^{2}+u^{2}}$ $u=2t-1$ $a=2$
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