Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 45

Answer

$\frac 1 4 arctan (\frac {2x+1} 8)+C$

Work Step by Step

$\int \frac 4 {4x^2+4x+65}dx$ $\int \frac 1 {(x+\frac 1 2)^2+16}dx$ $\frac 1 4 arctan (\frac {x+\frac 1 2} 4)+C$ $\frac 1 4 arctan (\frac {2x+1} 8)+C$
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