Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 44

Answer

$arcsec|2x-2|+C$

Work Step by Step

$\int \frac 1 {(x-1)\sqrt {4x^2-8x+3}}dx$ $\int \frac 1 {(x-1)\sqrt {(2x-2)^2-1}}dx$ $\int \frac 2 {(2x-2)\sqrt {(2x-2)^2-1}}dx$ $u=2x-2, du=2dx$ $\int \frac{du}{(u)\sqrt{u^2-1}}$ $\frac 1 a arcsec \frac {|u|} a +C$ $arcsec|2x-2|+C$
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