Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 42

Answer

$-e^{1/t}+C$

Work Step by Step

$\int e^{t^{-1}}t^{-2}dt$ $Let u = t^{-1}, du = -t^{-2}dt$ $-\int e^{t^{-1}}(-t^{-2})dt$ $-\int e^udu$ $-e^u+C$ $-e^{t^{-1}} +C$ $-e^{1/t}+C$
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