Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 39

Answer

$-\frac1 4 arcsin(4t-1)+C$

Work Step by Step

$\int \frac {-1}{\sqrt {1-(4t+1)^2}}dt$ $u=4t+1; du=4dt$ $-\frac1 4 \int \frac4 {\sqrt {1-(4t+1)^2}}dt$ $-\frac1 4 arcsin(4t-1)+C$
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