Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises - Page 512: 39

Answer

$-\frac1 4 arcsin(4t-1)+C$

Work Step by Step

$\int \frac {-1}{\sqrt {1-(4t+1)^2}}dt$ $u=4t+1; du=4dt$ $-\frac1 4 \int \frac4 {\sqrt {1-(4t+1)^2}}dt$ $-\frac1 4 arcsin(4t-1)+C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.