Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 29

Answer

$\frac 1{4\pi}sin2\pi x^2+C$

Work Step by Step

$\int x(cos2\pi x^2)$ $u=2\pi x^2; du=4\pi xdx$ $\frac 1{4\pi} \int (cos2\pi x^2)(4\pi x)dx$ $\frac 1{4\pi}sin2\pi x^2+C$
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