Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 8 - Integration Techniques, L'Hopital's Rule, and Improper Integrals - 8.1 Exercises: 26

Answer

$\frac 1 2 ln|2x+5|-\frac 1 2 ln|2x-5|+C$

Work Step by Step

$\int (\frac 1 {2x+5}- \frac 1 {2x-5})dx$ $\int \frac 1 {2x+5}$- $\int \frac 1 {2x-5}dx$ $u=2x+5; \frac 1 2 du=dx$ $u=2x-5;\frac 1 2 du=dx$ $\frac 1 2 \int \frac 1 u du-\frac 1 2 \int \frac 1 u du$ $\frac 1 2 ln|2x+5|-\frac 1 2 ln|2x-5|+C$
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